3.4 KiB
| cards-deck |
|---|
| electricity |
Ohms Law
Solve for voltage: #card
$\displaystyle V = I*R$ ^1654598090369
Solve for resistance: #card
$\displaystyle R = \frac{V}{I}$ ^1654598090389
Solve for current #card
$\displaystyle I = \frac{V}{R}$ ^1654598090398
Resistors in Series
#card
$R = R1 + R2 + R3 ...$ ^1654598090404
Resistors in Parallel
#card
\begin{flalign}
&\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3} ... &\\
\\
&\textit{For two resistors in parallel:} &\\
\\
&R = \frac{R1 * R2}{R1 + R2} &\\\
\end{flalign}
Tip: If resistors of the same value are in parallel the total resistance is a single resistor divided by the amount if resistors.
Voltage Divider
#card ^1654598090410
V_{out} = V_{in}(\frac{R_{1}}{R_1+R_2})
Thevenin’s Theorem
States that it is possible to simplify any linear circuit, no matter how complex, to an equivalent circuit with just a single voltage source and series resistance connected to a load.
Conservation of Charge (First Law)
#card
All current entering a node must also leave that node
\begin{flalign}
\sum{I_{IN}} = \sum{I_{OUT}}&&
\end{flalign}
Example: ^1654598090415
For this circuit kirchhoffs law states that:
\displaystyle i1 = i2 + i3 + i4
Conservation of Energy (Second Law)
All the potential differences around the loop must sum to zero.
\displaystyle \sum{V} = 0
Capacitors in Series
#card
$\displaystyle \frac{1}{C_{t}} = \frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}} ...$ ^1654598090421
Impedance in a Circuit
#card
\begin{flalign}
&Z = \sqrt{R^2 + X^2} &\\\
\\
&X = X_{L} - X_{C} \\
\end{flalign}
Capacitive Reactance
#card ^1654598090426
\displaystyle X_{c} = \frac{1}{2 \pi fC}
Inductive Reactance
#card
$\displaystyle X_{l} = 2\pi fL$ ^1654598090432
Analog Filters
Cutoff Frequency for RC Filters
#card
$\displaystyle f_{c} = \frac{1}{2\pi RC}$ ^1654598090437
Cutoff Frequency for RL Filters
#card
$\displaystyle f_{c} = \frac{R}{2\pi L}$ ^1654598090445
Cutoff Frequency for multiple Low Pass Filters
\displaystyle f_{(-3db)} = f_{c}\sqrt{2^{(\frac{1}{n})}-1}
Where n = Number if identical filters
Resonance Frequency for RLC Low Pass Filter
#card
$\displaystyle f_{o} = \frac{1}{2\pi \sqrt{LC}}$ ^1654598090452
Center Frequency with Fc and Fh
#card
$f_{c} = \sqrt{f_{h}*f_{l}}$ ^1654598090459
Filter Response for RC Filters
#card
$V_{out} = V_{in}(\frac{X_c}{\sqrt{R_{1}^2+X_{c}^2}})$ ^1654598090466
Cutoff Frequency \pi Topology Filter
#card
When the two capacitors have the same capacitance, it can be calculated like this: ^1654598090479
\displaystyle f_c = \frac{1}{4\pi\sqrt{LC}}
Angular Frequency (\omega)
#card
$\omega = 2\pi f = \frac{2\pi}{T}$ ^1654598090492
RLC Series Response
This is basically Ohms Law:
\displaystyle V = IZ
Where Z is the impedance:
Z = \sqrt{R^2 + (X_L - X_C)^2}
X_L = Reactive Inductance
X_C = Reactive Capacativw
Current through a transistor
\displaystyle I_{EQ} = \frac{V_{BB}-{V_{BE}}}{\frac{R_B}{(\beta+1)}+R_E}
Gain Bandwidth Product
#card
$GBP = A_V * f_c$ ^1654598090498
\displaystyle f_c = \frac{GBP}{A_V}
Bandwidth of Multiple OpAmps
Where n = number of stages
and BW = Bandwidth of single op-amp
BW_E = BW\sqrt{2^\frac{1}{n}-1}
Power lost in a Resistor
#card
$P = IV = I^2R = \frac{V^2}{R}$ ^1654598090504