23 lines
661 B
Markdown
23 lines
661 B
Markdown
The capacitor discharges in around 5RC, when we have an ac signal of 40Hz, and we want to match the frequency, we can calculate the following:
|
|
|
|
$$
|
|
\begin{flalign}
|
|
&\tau = RC &\\\
|
|
&f = 40Hz = \frac{1}{40}ds \\
|
|
&\textit{Lets put the resistor to 1k}\ohm\\
|
|
&\frac{1}{80} = 1000*C & | \div 1000 \\
|
|
&\frac{1}{80000} = C\\
|
|
&C = 12.5 \micro F\\
|
|
\end{flalign}
|
|
$$
|
|
```circuitjs
|
|
$ 1 0.000005 9.78399845368213 50 5 43 5e-11
|
|
R 80 224 0 224 0 2 40 5 0 0 0.5
|
|
c 80 224 192 224 0 0.00001 -1.936025478465976 0.001
|
|
r 192 224 192 304 0 1000
|
|
g 192 304 192 336 0 0
|
|
O 192 224 304 224 0 0
|
|
o 4 64 0 151554 10 0.1 0 1
|
|
o 0 64 0 151554 10 0.1 0 2 0 3
|
|
```
|
|
![[spike-circuit-rc-relation.png]] |