notes/Resources/electricity/formulas.md
2023-04-20 12:25:26 +00:00

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Ohms Law

Solve for voltage:

\displaystyle V = I*R

Solve for resistance:

\displaystyle R = \frac{V}{I}

Solve for current

\displaystyle I = \frac{V}{R}

Resistors in Series

R = R1 + R2 + R3 ...

Resistors in Parallel

\frac{1}{R} = \frac{1}{R1} + \frac{1}{R2} + \frac{1}{R3} ... \\
\textit{}\\
\textit{For two resistors in parallel:}\\
\textit{}\\
R = \frac{R1 * R2}{R1 + R2}

Tip: If resistors of the same value are in parallel the total resistance is a single resistor divided by the amount if resistors.

Voltage Divider

V_{out} = V_{in}(\frac{R_{1}}{R_1+R_2})

Thevenins Theorem

States that it is possible to simplify any linear circuit, no matter how complex, to an equivalent circuit with just a single voltage source and series resistance connected to a load.

Conservation of Charge (First Law)

All current entering a node must also leave that node

\sum{I_{IN}} = \sum{I_{OUT}}

Example:

For this circuit kirchhoffs law states that:

\displaystyle i1 = i2 + i3 + i4

Conservation of Energy (Second Law)

All the potential differences around the loop must sum to zero.

\displaystyle \sum{V} = 0

Capacitors in Series

\displaystyle \frac{1}{C_{t}} = \frac{1}{C_{1}}+\frac{1}{C_{2}}+\frac{1}{C_{3}} ...

Impedance in a Circuit

Z = \sqrt{R^2 + X^2} \\
\textit{}\\
X = X_{L} - X_{C} \\ 

Capacitive Reactance

\displaystyle X_{c} = \frac{1}{2 \pi fC}

Inductive Reactance

\displaystyle X_{l} = 2\pi fL

Analog Filters

Cutoff Frequency for RC Filters

\displaystyle f_{c} = \frac{1}{2\pi RC}

Cutoff Frequency for RL Filters

\displaystyle f_{c} = \frac{R}{2\pi L}

Cutoff Frequency for multiple Low Pass Filters

\displaystyle f_{(-3db)} = f_{c}\sqrt{2^{(\frac{1}{n})}-1}

Where n = Number if identical filters

Resonance Frequency for RLC Low Pass Filter

\displaystyle f_{o} = \frac{1}{2\pi \sqrt{LC}}

Center Frequency with Fc and Fh

f_{c} = \sqrt{f_{h}*f_{l}}

Filter Response for RC Filters

V_{out} = V_{in}(\frac{X_c}{\sqrt{R_{1}^2+X_{c}^2}})

Cutoff Frequency \pi Topology Filter

When the two capacitors have the same capacitance, it can be calculated like this:

\displaystyle f_c = \frac{1}{4\pi\sqrt{LC}}

Angular Frequency (\omega)

\omega = 2\pi f = \frac{2\pi}{T}

RLC Series Response

This is basically Ohms Law:

\displaystyle V = IZ

Where Z is the impedance:

Z = \sqrt{R^2 + (X_L - X_C)^2}

X_L = Reactive Inductance X_C = Reactive Capacativw

Current through a transistor

\displaystyle I_{EQ} = \frac{V_{BB}-{V_{BE}}}{\frac{R_B}{(\beta+1)}+R_E}

Gain Bandwidth Product

GBP = A_V * f_c
\displaystyle f_c = \frac{GBP}{A_V}

Bandwidth of Multiple OpAmps

Where n = number of stages and BW = Bandwidth of single op-amp

BW_E = BW\sqrt{2^\frac{1}{n}-1}

Power lost in a Resistor

P = IV = I^2R = \frac{V^2}{R}