23 lines
661 B
Markdown
23 lines
661 B
Markdown
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The capacitor discharges in around 5RC, when we have an ac signal of 40Hz, and we want to match the frequency, we can calculate the following:
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$$
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\begin{flalign}
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&\tau = RC &\\\
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&f = 40Hz = \frac{1}{40}ds \\
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&\textit{Lets put the resistor to 1k}\ohm\\
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&\frac{1}{80} = 1000*C & | \div 1000 \\
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&\frac{1}{80000} = C\\
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&C = 12.5 \micro F\\
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\end{flalign}
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$$
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```circuitjs
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$ 1 0.000005 9.78399845368213 50 5 43 5e-11
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R 80 224 0 224 0 2 40 5 0 0 0.5
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c 80 224 192 224 0 0.00001 -1.936025478465976 0.001
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r 192 224 192 304 0 1000
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g 192 304 192 336 0 0
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O 192 224 304 224 0 0
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o 4 64 0 151554 10 0.1 0 1
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o 0 64 0 151554 10 0.1 0 2 0 3
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```
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![[spike-circuit-rc-relation.png]]
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